[Offer收割]编程练习赛40 register

Ended

Participants:189

Verdict:Wrong Answer
Score:0 / 100
Submitted:2017-12-17 13:36:49

Lang:G++

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#include <stdio.h>
#define N 1000
int data[N][N];
int main(void){
    int n,m;
    int ans=0;
    scanf("%d%d",&n,&m);
    for(int i=0;i<n;i++)
        for(int j=0;j<n;j++)
            scanf("%d",&data[i][j]);
    for(int i=0;i<n-2;i++)
        for(int j=0;j<m-2;j++){
            int sum1,sum2,sum3,sum4,sum5,sum6,sum7,sum8,sum;
            sum1=data[i][j]+data[i][j+1]+data[i][j+2];
            sum2=data[i+1][j]+data[i+1][j+1]+data[i+1][j+2];
            sum3=data[i+2][j]+data[i+2][j+1]+data[i+2][j+2];
            
            sum4=data[i][j]+data[i+1][j]+data[i+2][j];
            sum5=data[i][j+1]+data[i+1][j+1]+data[i+2][j+1];
            sum6=data[i][j+2]+data[i+1][j+2]+data[i+2][j+2];
            
            sum7=data[i][j]+data[i+1][j+1]+data[i+2][j+2];
            sum8=data[i+2][j]+data[i+1][j+1]+data[i][j+2];
            if(sum1==sum2&&sum2==sum3&&sum3==sum4&&sum4==sum5
            &&sum5==sum6&&sum6==sum7&&sum7==sum8)
                ans++;
        }
    
    printf("%d\n",ans);
    return 0;
}
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